Monday, August 27, 2012

cluster users by attributes

A massive social network decided to assign an unsigned int as unique id for each user. Also, each user has a set of attributes represented as string and integers. Define a suitable cluster strategy for users based on the common attributes.

Sunday, August 26, 2012

Intersect two sorted arrays

Given two arrays A and B, where #A = m and #B = n, how would you intersect A and B? Please discuss complexity and real optimization

Saturday, August 25, 2012

Sum maximum

Given an array of n positive integers. Write a program to find the sum of maximum sum subsequence of the given array such that the intgers in the subsequence are sorted in increasing order.

Thursday, August 23, 2012

Sequences in sorted order

Given two integers k and n, write a function that prints all the sequences of length k composed of numbers 1,2..n. You need to print these sequences in sorted orde

Wednesday, August 22, 2012

Find the minimum distance

Given an unsorted array arr[] and two numbers x and y, find the minimum distance between x and y in arr[]. The array might also contain duplicates. You may assume that both x and y are different and present in arr[]

Sunday, August 19, 2012

Bing and Windows 8

Apparently, I am in the video (someone told me ;))

Saturday, August 18, 2012

Autosuggest and Bing

My team is shipping this Autosuggest Backend

 "“As you type results, Bing will offer suggestions and if we do say so, the auto-completion feels pretty quick.”"

http://www.engadget.com/2012/08/15/windows-8-rtm-whats-new/

Thursday, August 16, 2012

Subset sum

Find subset of elements that are selected from a given set whose sum adds up to a given number K. The set contains non-negative values.

Wednesday, August 15, 2012

Special Stack

Design a Data Structure SpecialStack that supports all the stack operations like push(), pop(), isEmpty(), isFull() and an additional operation getMin() which should return minimum element from the SpecialStack

Tuesday, August 14, 2012

Count in an array

Write a function to count number of smaller elements on right of each element in an array.

Monday, August 13, 2012

Celebrity problem

In a party of N people, only one person is known to everyone. Such a person may be present in the party, if yes, (s)he doesn’t know anyone in the party. We can only ask questions like “does A know B? “. Find the stranger (celebrity) in minimum number of questions

Saturday, August 11, 2012

Longest Bitonic distance

Given an array arr[0 ... n-1] containing n positive integers, a subsequence of arr[] is called Bitonic if it is first increasing, then decreasing.

Thursday, August 9, 2012

Saturday, August 4, 2012

Intersection and Union

Given two Linked Lists, create union and intersection lists that contain union and intersection of the elements present in the given lists. Discuss complexity and make your assumptions.

Thursday, August 2, 2012

Bing and Facebook




“Facebook is a partner with Google’s biggest rival, Bing, to handle web searches.”


“Readers: Are you seeing the “search the Web” link in your typeahead search results?”


“Facebook had previously allowed users to filter their Facebook searches by web results after clicking over to a main results page, but it hadn’t offered the option from the typeahead, which only included Facebook objects. Making it more efficient to search the web from Facebook’s search bar will give users an incentive to use Facebook search rather than going to a separate search engine like Google. “

Wednesday, August 1, 2012

An hidden gem, not so well known: Academic Search Microsoft. Want it integrated in bing?

http://academic.research.microsoft.com/Author/77558/antonio-gulli?query=antonio+gull



Antonio Gulli 
Publications: 22 | Citations: 522 | G-Index: 22 | H-Index: 11 
Collaborated with 10 co-authors from 1997 to 2009; Cited by 905 authors
 Homepage |  Bing

Tuesday, July 31, 2012

Sharing revenues with skilled friends

In my previous postings I discussed about the opportunity of explicitly share your skills on facebook showing  that the authenticity of those skills would be self-regulated by the social network. Also, I claimed that the current web search ads system is not necessarily the only monetization model available.  In web search, when a query is submitted some relevant content is retrieved and ads are sold together with the results. The engine takes the money and the web content producers take no money. Web content producers take benefits from the traffic received by the search engine, but they directly take no money -- which is strange to me.

Now the question is what incentive could we give the users who are sharing their own skills?

First answer would be to send them traffic in analogy to what happen in web search. Anyway, I am not sure that this would be valuable for my friend Giuseppe who claimed that he is an expert in Photography. Why sending traffic to his Facebook page should have any additional value to him?

The second answer is to share revenue between my skilled friend Giuseppe and Facebook whenever Facebook shows Giuseppe among the friends skilled in Photography. The more likes Giuseppe gets the higher would be the chances to be retrieved for a search about Photography. Whenever ads shown for that topic are clicked Giuseppe will get a little amount of the revenues generated. He produced the content, he has the skill so he takes some direct money for it. In my view, this model would give a natural incentive to share skills and to get likes for those skills.

The third answer is still to about sharing revenues, but would be based on inserting ads into skilled pages. What is a skilled page? pretty simple. If Giuseppe declares a skill in Photography he can create a special page on his profile very similar to the traditional timeline but focused just on Photography. All the ads shown in that page are about the Photograpy topic and again there should be some form of revenue sharing as form of incentive to produce high quality, curated skilled pages. After all, Giuseppe is the expert so he has to tell something about his expertise. 

Monday, July 30, 2012

Skilled friends can gain money after they share their skills for free

An anonymous reader told me: "people need an incentive/experience to provide this information for free. They will assume that their friends know - so why should they tell Facebook this information?"

In my previous posting, I showed that skills cannot be faked because they are judged by the rest of the friends. This is nothing but just applying the power of social ties which self-regulates authenticity.

Now, let's go to the next step. I believe that current web ads system is fundamentally flawed. A lot of people produce web content which is then indexed by search engines. When a query about a topic is submitted by a user some relevant content is retrieved and ads are sold together with the results. The engine takes the money and the content producers take no money.

Why that?

Yes, content producers will receive more traffic and this has certainly an economic value. Anyway, who said that this is the only model we can think of?

Do you have any alternative?

Sunday, July 29, 2012

Skills cannot be faked

One more thought about my idea of skilled friends on Facebook. I don't believe the a friend can mystify her skills by declaring a talent which is not there. Her social network will understand this and she will look bad in front of her friends.

So, skills cannot be faked. Plus, when you declare a skill there is always the opportunity to like it and this will be an important signal to rank friends by skills.

Saturday, July 28, 2012

An idea for Facebook: from friends to skilled friends (or how to make money)

Facebook has 900 millions of users, and everyone is connected to a number of friends. Sometime you don't know what are your friends' skills. In my network there are people expert in photography, people expert in art, people experts in skiing, people expert in surfing, and people expert in solar power, and people expert in philosophy, and people with an immense musical background, and many geeks, and people with tremendous interest for electrical cars, and people with a passion for astronomy and celestial stuffs, and ....

So many people, so much talent to discover.

So Facebook, let everyone declare their own skills and talents to their social network. Let my friends be skilled friends. Let me also tag the skills of my friends as I tag my friends' faces in pictures.

Then, let me discover this talent when I search:  if I search for photography give the name of my friend Giuseppe who has a skill in this subject, and If I search surfing give me the name of Luca who is the expert here. If no friend is an expert in that topic, please find a skilled expert among the friends of my friend.

Transform generic search in search for skilled friends.

And when I search a skill, here you have the magic opportunity to sell ads about that topic. 

So If i search for surfing give me the name of Luca, but also ads related to the topic. Give me the name of that online market where I can buy great surf tables or show me where to find swimsuits. Likewise, if I search for camera give me the name of Giuseppe but also ads for the latest Nikon D7000. And...

Transform generic search in a search for skilled friends, and make money out of a great user experience.

Thursday, July 26, 2012

Bing search meets Facebook: exciting typeahead progress

Very happy about the integration of typeahead/autosuggestion technologies between Bing and Facebook. Now you can Bing directly from Facebook search box. Congratulation to the teams that made this happening by establishing a collaboration with several locations in the world (California, Washington, and London). My team in London provided core backend technologies for Bing Autosuggestion.

Enjoy!








Wednesday, July 25, 2012

A phone has two sides. An idea for phone manifactures

Yesterday, I was listening this conversation: "I have always to carry at least two phones. My iphone is great for browsing and the apps, and my blackberry is great for browsing emails". How many of you have a similar  experience: either you have a phone with a large touch display which is great for browsing, or you have a phone with smaller display but with a decent keyboard. So you go out of there and buy your favourite Android, Windows Phone, Iphone AND you possibly buy a traditional Blackberry or the like.

Now I wonder why two devices? Why don't have just one with two sides? On one side you have the large touch display, and on the other side you have the smaller display but a good traditional keyboard.

I should probably patent this idea and sell it to companies out of there, but there is a war so I prefer to publish here and give it for free.. as in freedom

Sunday, July 22, 2012

LRU

How to implement LRU caching scheme? What data structures should be used

Saturday, July 21, 2012

Friday, July 20, 2012

Thursday, July 19, 2012

Bitonic arrays

iven an array A[0 ... n-1] containing n positive integers, a subarray A[i ... j] is bitonic if there is a k with i <= k <= j such that A[i] <= A[i + 1] ... <= A[k] >= A[k + 1] >= .. A[j - 1] > = A[j]. Write a function that takes an array as argument and returns the length of the maximum length bitonic subarray.

Wednesday, July 18, 2012

Array and positions

Given an array of n distinct integers sorted in ascending order, write a function that returns true is there is an index i such that arr[i] is equal to i

Tuesday, July 17, 2012

Strange struct.


struct str
{
    int i: 1;
    int j: 2;
    int k: 3;
    int l: 4;
};

what is this? is it a good and portable code?

Monday, July 16, 2012

Two arrays

Given two sorted arrays of any length, find out the median of them if they are sorted into single array

Saturday, July 14, 2012

Maze


Write a program to find all the possible paths from a starting point to dest point in a maze(2-D array).
ex: 1 0 1 0
 1 1 1 1
 0 1 0 1
 0 0 1 1 
If there is a block it’s represented by 0.
If there is a path it’s represented by 1.

Friday, July 13, 2012

Beautification

Write a program for beautificaion of a program file in an IDE

Thursday, July 12, 2012

Linked list

Write a program to print the n-nodes from tail of the linked list.

Wednesday, July 11, 2012

IPv4

Write a program to Validate an IPv4 Address

Tuesday, July 10, 2012

Distributed sort

Given N machines. Each machine contains some numbers in sorted form. The amount of numbers for each machine is not fixed. Output the numbers from all the machine in sorted non-decreasing form.

Monday, July 9, 2012

Unique words

Design a system to calculate the number of unique words in a file.. 1) What if the file is huge ? 2) Assuming that you have more than one computers available, how can you distribute the problem ?

Sunday, July 8, 2012

Array of 0 and 1

You have an array of 0s and 1s and you want to output all the intervals (i, j) where the number of 0s and numbers of 1s are equal. linear

Wednesday, July 4, 2012

Sum 3 numbers

given an array and a target value. Find a,b,c such that a+b+c=target

Monday, July 2, 2012

Solve the coin change problem

def count( n, m ): if n == 0: return 1 if n < 0: return 0 if m <= 0 and n >= 1: #m < 0 for zero indexed programming languages return 0 return count( n, m - 1 ) + count( n - S[m], m )

Sunday, July 1, 2012

Regexp match

Write a function checkRegex() which takes two strings as input, one string represents a regex expression and other is an input string to match with the regex expression. Return true if it matches, else false. Regex may contain characters ‘a-z’, ‘.’ and ‘*’ where ‘.’ matches any character and ‘*’ means 0 or more occurrences of the previous character preceding it.

Saturday, June 30, 2012

Min and Max

Find the min and max in an array. Now do it in less than 2n comparisons

Friday, June 29, 2012

Event store

Question: Design a component that implements the following functionality.. 1) Record an Event (For the sake of simplicity, treat the Event as an integer code) 2) Return the number of Events recorded in the last one minute. 3) Return the number of Events recorded in the last one hour. i.e implement the following interface

Thursday, June 28, 2012

Points closer to a point

You are given a list of points in the plane, write a program that outputs each point along with the three other points that are closest to it. These three points ordered by distance.

Wednesday, June 27, 2012

Last 60secs

Create a data structure which is supposed to log number of user requests per second. At any point of time your boss can ask you the number of hits for the last 60 seconds.

Monday, June 25, 2012

Reverse words

Given a file with billions of records data. The file is too large to in main memory, and you need to reverse each word in that file and then save the reversed words to another file.

Sunday, June 24, 2012

Creative d80 -- Bluetooth wireless music box

I recently bought a Creative d80 -- Bluetooth wireless music box and my impression is WOW!! It is very cheap just less than $40 and the quality of music is impressive. I can stream over Bluetooth from my iphone, ipad, android, winphone, and windows 7. I don't have a Mac but it seems as easy as the remaining ones. If you have win7 make sure that your Bluetooth device has a stack supporting a2dp or enhanced data rate.

Geek is about founding creative and inexpensive cool technologies.

Saturday, June 23, 2012

Monday, June 18, 2012

maximal subsets

Given a set S, find all the maximal subsets whose sum <= k. For example, if S = {1, 2, 3, 4, 5} and k = 7 Output is: {1, 2, 3} {1, 2, 4} {1, 5} {2, 5} {3, 4}

Saturday, June 16, 2012

Value of A and B

Given two sorted positive integer rrays A(n) and B(n). We define a set S = {(a,b) such that a in A and b in B}. Obviously there are n^2 elements in S. The value of such a pair is defined as Val(a,b) = a + b. Now we want to get the n pairs from S with largest values. The tricky part is that we need an O(n) algorithm.

Friday, June 15, 2012

true and false

Given a function bool Zoo(int x) and its called for y times , how you will generate the true with probability x/y times .

Thursday, June 14, 2012

what's next?

 
1
 
 
1 1
 
 
2 1
 
 
1 2 1 1

Wednesday, June 13, 2012

Eggdrops

Solve the classical Google's interview problem.

Dynamic programming


k: Number of floors
n: Number of Eggs
eggDrop(n, k): Minimum number of trails needed to find the critical
               floor in worst case.


1) If the egg breaks after dropping from xth floor, then we only need to check for floors lower than x with remaining eggs; so the problem reduces to x-1 floors and n-1 eggs
2) If the egg doesn’t break after dropping from the xth floor, then we only need to check for floors higher than x; so the problem reduces to k-x floors and n eggs.

eggDrop(n, k) = 1 + min{max(eggDrop(n - 1, x - 1), eggDrop(n, k - x)): 
                 x in {1, 2, ..., k}}

Tuesday, June 12, 2012

Monday, June 11, 2012

A feature request for Facebook

Sometime I just want to pin a thread and follow it without expressing an explicit like. Would it be possible to just follow a thread?

Sunday, June 10, 2012

Monetizing free login

Several different providers are offering universal login schema, including Microsoft, Linkedin and Facebook. Apparently, none is monetizing this phase while there are plenty of opportunities to be leveraged.

Let's analyse a simple scenario where Alice, a Spotify user, decides to login using her Facebook account. Facebook knows Alice's geo-location, Alice's profile, Alice's past postings and likes. So Facebook has a lot of information to be mined for serving ads while Spotify does not have the same information. In other words, Facebook can sell ads to Spotify's users. So this could be the "Adsense" program for Facebook.

So my question is why Facebook is not opening this ads platform?


Saturday, June 9, 2012

Stars

Find the closest stars in the sky

Thursday, June 7, 2012

Phonebook

Data structure TO use to design a phonebook. What is time complexity for retrieving, adding, and deleting entries

Monday, June 4, 2012

Write a function that takes 2 arguments: a binary tree and an integer n, it should return the n-th element in the inorder traversal of the binary tree

int findNthElementByInorder(Node *node, int &n)
{
    if (node == null)
        return -1;
    findNthElementByInorder(node->left, n);
    if (n == 0)
        return node-> value;
    else
       n--;
   findNthElementByInorder(node->right, n);
}

N-th

Write a function that takes 2 arguments: a binary tree and an integer n, it should return the n-th element in the inorder traversal of the binary tree.
int findNthElementByInorder(Node *node, int &n)
{
    if (node == null)
        return -1;
    findNthElementByInorder(node->left, n);
    if (n == 0)
        return node-> value;
    else
       n--;
   findNthElementByInorder(node->right, n);
}

Sunday, June 3, 2012

Reverse a linked list

Node* reverseLL(Node* n) {
   Node* curr = n;
   Node* prev = null;
   while(curr !=null) {
        Node* temp = curr.next;
        curr.next = prev;
        prev = curr;
        curr = temp;
   }
   return prev;
}

Saturday, June 2, 2012

Duch national problem

void threeWayPartition(int data[], int size, int low, int high) {
  int p = -1;
  int q = size;
  for (int i = 0; i < q;) {
    if (data[i] < low) {
      swap(data[i], data[++p]);
      ++i;
    } else if (data[i] >= high) {
      swap(data[i], data[--q]);
    } else {
      ++i;
    }
  }

Friday, June 1, 2012

Given array find 3 elements that sum up to 0



For each i = 1..length do
  left = 0, right = length
  While left < i and right > i do
     if values[left] + values[i] + values[right] == 0
      # Got solution here
    if values[left] + values[i] + values[right] > 0
      # means that right border should be moved
      right--
   else
     # moving left border
      left++

Thursday, May 31, 2012

Sort an array of objects

There are just three sizes large, small, medium. what is the optimal complexity? Can you make this in-place?

Wednesday, May 30, 2012

Given 2 very large numbers, each of which is so large it can only be represented as an array of integers, write a function to multiply them


const unsigned MULTIPLY_BASE = 10;

void multiplyLittleEndian(const vector < unsigned > &a, const vector < unsigned > &b, vector < unsigned >  &r)
{
    r.assign(a.size()+b.size(), 0);
    unsigned ri=0;
    for(unsigned ai=0; ai < a.size(); ++ai)
    {
        unsigned cri = ri++, carry = 0, am = a[ai], cr;
        for(unsigned bi=0; bi < b.size(); ++bi, ++cri)
        {
            cr = carry + am*b[bi] + r[cri];
            r[cri] = cr % MULTIPLY_BASE;
            carry = cr / MULTIPLY_BASE;
        }
        while(carry)
        {
            cr = carry + r[cri];
            r[cri++] = cr % MULTIPLY_BASE;
            carry = cr / MULTIPLY_BASE;
        }
    }
    while((!r.empty()) && r.back() == 0) r.pop_back(); // trim result
}

Sunday, May 27, 2012

add two numbers represented by strings

First need to reverse both strings, then add char by character and reverse final String again.

Friday, May 25, 2012

Interweave a linked list

Interweave a linked list. Do it in Linear time and constant space. Input: A->B->C->D->E Output: A->E->B->D->C

Wednesday, May 23, 2012

Tuesday, May 22, 2012

Roman strings

Get numeric number out of a roman string, linear time Given: mapping I = 1, V = 5, X = 10, L = 50, C = 100, D = 500, M = 1000 Input/Output: II = 2, III = 3, IV = 4 VI, VII, VIII IX = 9 XL = 40, XLIX = 49

mapping = {
            'I' : 1,
            'V' : 5,
            'X' : 10,
            'L' : 50,
            'C' : 100,
            'D' : 500,
            'M' : 1000,
          }

def roman(string):
  prev = 0
  totalsum = 0

  for c in string:
    if mapping[c] <= prev:
      totalsum = totalsum + mapping[c]
    else:
      totalsum = totalsum - prev
      totalsum = totalsum + mapping[c] - prev

    prev = mapping[c]

  print(totalsum)

roman("XCIX")